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11/8一2/5十5/8一3/5怎算简便算

11/8一2/5十5/8一3/5 =11/8十5/8一(2/5+3/5) =2-1 =1

2/5十5/11十6/11 =2/5+(5/11+6/11) =1.4 5/12十3/8十7/12一3/8 =5/12+7/12 =1 16/13一5/9十1O/13一4/9 =16/13+10/13-(5/9+4/9) =1 8一2/5一8/5 =8-(2/5+8/5) =6 13/20一(3/20一1/3)=1/2+1/3 =5/6 (7/8一7/6)十(1/8十1/6) =(7/8+1/8)-(7/6-...

2+5+8+11……+23 =(2+23)×8÷2 =25×8÷2 =100

解:原式=5/8-(1/2*5/11+3/5*5/11) =5/8-(5/22+3/11) =5/8-(5/22+6/22) =5/8-11/22 =5/8-1/2 =5/8-4/8 =1/8

3/(2×5)=(5-2)/(2×5)=1/2-1/5 同理, 3/(5×8)=1/5-1/8 3/(8×11)=1/8-1/11 3/(11×14)=1/11-1/14 3/(14×17)=1/14-1/17 3/(17×20)=1/17-1/20 相加得到,(中间抵消了很多项) 原式=1/2-1/20=9/20

2/5加上3/8乘以2/5=2/5(1+3/8)=2/5×11/8=11/20 乘法分配律反运算,提取2/5.

采纳哦

5/8-(1/2+3/5)×5/11=5/8-(5/22+3/11)==5/8--1/2=1/8

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